Hi I found a few things about the Analog Input of the Analog Discovery, but I'm not really sure what it means.
Analog Inputs:
Accuracy (scale≤0.5V/div, VinCM = 0V): ±10mV±0.5%
Accuracy (scale≥1V/div, VinCM = 0V): ±100mV±0.5%
I got this from the website, but I don't know what this ±10mV±0.5% means. So if anyone knows what this means please tell me.
Best regards
Mathias Müller